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Simplifying (2x + 1)(2x + 1) = 4(x2 + x + 1) Reorder the terms: (1 + 2x)(2x + 1) = 4(x2 + x + 1) Reorder the terms: (1 + 2x)(1 + 2x) = 4(x2 + x + 1) Multiply (1 + 2x) * (1 + 2x) (1(1 + 2x) + 2x * (1 + 2x)) = 4(x2 + x + 1) ((1 * 1 + 2x * 1) + 2x * (1 + 2x)) = 4(x2 + x + 1) ((1 + 2x) + 2x * (1 + 2x)) = 4(x2 + x + 1) (1 + 2x + (1 * 2x + 2x * 2x)) = 4(x2 + x + 1) (1 + 2x + (2x + 4x2)) = 4(x2 + x + 1) Combine like terms: 2x + 2x = 4x (1 + 4x + 4x2) = 4(x2 + x + 1) Reorder the terms: 1 + 4x + 4x2 = 4(1 + x + x2) 1 + 4x + 4x2 = (1 * 4 + x * 4 + x2 * 4) 1 + 4x + 4x2 = (4 + 4x + 4x2) Add '-4x' to each side of the equation. 1 + 4x + -4x + 4x2 = 4 + 4x + -4x + 4x2 Combine like terms: 4x + -4x = 0 1 + 0 + 4x2 = 4 + 4x + -4x + 4x2 1 + 4x2 = 4 + 4x + -4x + 4x2 Combine like terms: 4x + -4x = 0 1 + 4x2 = 4 + 0 + 4x2 1 + 4x2 = 4 + 4x2 Add '-4x2' to each side of the equation. 1 + 4x2 + -4x2 = 4 + 4x2 + -4x2 Combine like terms: 4x2 + -4x2 = 0 1 + 0 = 4 + 4x2 + -4x2 1 = 4 + 4x2 + -4x2 Combine like terms: 4x2 + -4x2 = 0 1 = 4 + 0 1 = 4 Solving 1 = 4 Couldn't find a variable to solve for. This equation is invalid, the left and right sides are not equal, therefore there is no solution.
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